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Solved example
Ex-1: Consider a sequence 2, 3/2 , 4/3 , 5/4, …….. here Sn = 1 + 1/n A1. From the given sequence we can see that the sequence Sn is convergent. \(\lim_{n \rightarrow\ \infty}S_{n}\) =\(\lim_{n \rightarrow\ \infty}(1+\frac{1}{n})\) =\(1+\frac{1}{\infty}\) =\(1+0\) =\(1\) Since the limit of the sequence is 1, therefore the sequence Sn is convergent . Ex-2: Consider a sequence Sn= n² + (-1)ⁿ. A2. From the given sequence we can see that the sequence sn is divergent. \(\lim_{n \rightarrow\ }S_{n} \) =\(\lim_{n \rightarrow\ \infty} n^{2} + (-1)^{n}\) =\(\infty^{2} + (-1)^{\infty}\) =\(\infty\) Since the limit of the sequence is \(\infty\), therefore the sequence Sn is diververgent . Ex-3.Consider a sequence \9Sn=\frac{n^{2}+2}{n^{2}+5}\). A2. From the given sequence we can see that the sequence sn is divergent. \(\lim_{n \rightarrow\ \infty}S_{n}\) =\(\lim_{n \rightarrow\ \infty}\frac{n^{2}+2}{n^{2}+5} \) =\(\lim_{n \rightarrow\ \infty}\frac{n^{2}(1+\frac{2}{n^{2}})}{n^{2}(1+\frac{5}{n^{2}})} \) =\(\lim_{n \rightarrow\ \infty}\frac{(1+\frac{2}{n^{2}})}{(1+\frac{5}{n^{2}})} \) = \(\frac{1}{1}) =\(1\). Since the limit of the sequence is 1, therefore the sequence Sn is convergent . Now learning is easy and fun for the students with the Testbook app. This app is specially curated for students preparing for national entrance examinations. It has notes curated by the experts and mock tests which are developed while keeping the nature of the examination. It is available on both iOS and Android versions of the phone. Download your Testbook App from here now, and get discounts on your first purchase order. |
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